Engineering

Heat Conduction

Steady-state: Q = k·A·ΔT / L

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k (W/m·K)

Area A (m²)

ΔT (K)

Thickness L (m)

k mineral wool ≈ 0.035–0.045, brick ≈ 0.6, steel ≈ 50 W/m·K.

How it works

Calculate steady-state heat flow through a flat wall.

Who it's for: HVAC and building engineers estimating heat loss through assemblies.

Q = k·A·ΔT/L for one-dimensional conduction.

k = thermal conductivity; L = wall thickness.

Result in watts for given area and temperature difference.

Enter thermal conductivity k, Area A, Temperature difference ΔT, and thickness L.
Read heat flow Q.